Translation Statement
Conversion Formula
Grade Point Average Calculations
Conversion of Grades of 3
Course Equivalences
Program Rules
 


Example 1: A student studied a year part-time in a Bachelor of Arts (4 subjects; 10 credit points each) before Unitisation occurs. For these subjects, the student attains the following grades: 6, 5, 4, 5. The student then studies another semester part-time (2 subjects; 2 units each), and attains the following grades: 4, 5. The student’s cumulative GPA needs to be calculated.

WORKING

Before unitisation, the student studied 40 #.

U1 = (16 x 40 x 3) /240 = 8

The GPAa in the equation (where  grades obtained pre-unitisation are factored in) is:

GPAa =     S (CPn x Gn)
                ___________

                    S CPn

= (10x6 + 10x5 + 10x4 + 10x5)
_________________________

            10+10+10+10

= 60+50+40+50
______________

            40

= 5

After unitisation, the student undertook 4 units.

U2 = 4 units

The GPA b in the equation (where grades obtained post-unitisation are factored in) is:

GPAb = S (Un x Gn)
             ___________

                    S Un

= (2x4 + 2x5)
____________

            4

= (8+10) / 4

= 4.5

Thus, if

Cumulative GPA = (GPAa x U1) + (GPAb x U2)
                            ________________________

                                        U1+ U2

Then,

= (5 x 8) + (4.5 x 4)
________________

           8 + 4

= 40 + 18
________

    12

= 4.83.

The student’s cumulative GPA = 4.83.

Example 2: A student began her study in a Bachelor of Science. In her first year, she studied only what she needed to to obtain a new rank for upgrading purposes (80#). She studied several subjects in that year: four 12 # subjects in which she achieved the following grades: (5,5,6,7); two 10 # subjects in which she attained the following grades: (5, 6); and two 6 # subjects in which she attained the following grades: (6, 7).

She successfully applied through QTAC for entry to Physiotherapy and began studying this different course the following year. In this year she studied the following subjects from the first-year schedule for Physiotherapy and attained the following grades: 9# (4); 10# (4); 5# (5); 10# (4); 8# (5); 6# (6); 10# (4); 20# (4); 18# (5).

Then Unitisation came in.

In her second year of Physiotherapy, she studied 6 two-unit subjects (4,5,6,4,4,4) and 1 four-unit subject (4).

The first aim is to calculate the Total Cumulative Grade Point Average.

WORKING
In our equation we will have two GPAa s. ie. we will have GPAa1 for Science and GPAa2 for Physiotherapy, as two programs contribute to the grades prior to unitisation. We will also have two U1s ie. we will have U1a for Science and U1b for Physiotherapy.

Before unitisation, under Science, the student studied 80 #.

U1a = (16 x 80 x 3) / 290 = 13.24 (rounded)

This student has completed approximately 13.24 units pre unitisation under Science.

Before unitisation, under Physiotherapy, the student studied 96 #.

U1b = (16 x 96 x 4) / 379 = 16.21 (rounded)

This student has completed approximately 16.21 units pre-unitisation under Physiotherapy.

GPAa1 = S (CPn x Gn)
                __________    (for those subjects studied under Science)

                            S CPn

= (12x5 + 12x5 + 12x6 + 12x7 + 10x5 + 10x6 + 6x6 + 6x7)
________________________________________________

                    12+12+12+12+10+10+6+6

= (60+60+72+84+50+60+36+42)
____________________________

                                    80

= 5.8

GPAa2 = S (CPn x Gn)
                ___________      (for those subjects studied under Physiotherapy)

                              S CPn

= (9x4 + 10x4 + 5x5 + 10x4 + 8x5 + 6x6 + 10x4 + 20x4 + 18x5)
___________________________________________________

                                9+10+5+10+8+6+10+20+18

= (36+40+25+40+40+36+40+80+90)
______________________________

                                96

= 4.45

After unitisation, the student undertook 16 units in her second year of Physiotherapy.

U2 = 16

The GPA b in our equation (where we factor in the grades obtained post-unitisation) is:

GPAb = S (Un x Gn)
            ___________

                    S Un

= (2x4 + 2x5 + 2x6 + 2x4 + 2x4 + 2x4 + 4x4)
_____________________________________

                        2+2+2+2+2+2+4

= (6+10+12+8+8+8+16)
_____________________

                    16

= 4.25

Thus, if

Total Cumulative GPA = (GPAa1 x U1a) + (GPAa2 x U1b) + (GPAb x U2)
                                        _____________________________________

U1a + U 1b + U2

Then,

= (5.8 x 13.24) + (4.45 x 16.21) + (4.25 x 16)
_____________________________________

                13.24 + 16.21 + 16

= (76.79 + 72.13 + 68)
___________________

            45.45

= 4.77

The student’s total cumulative GPA = 4.77.

Example 3: To calculate only the Cumulative GPA for this student, you simply use only those numbers relevant to the Physiotherapy studies.

Ie.

Cumulative GPA = (GPAa2 x U1b) + (GPAb x U2)
                               ________________________

U1b + U2

           

= (4.45 x 16.21) + (4.25 x 16)
________________________

16.21 + 16

 

= (72.13 + 68)
____________

        32.21

= 4.35.

The student’s cumulative GPA = 4.35.

 
 
 
 
 
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